Anyone following me here?
So who's carrying a full bag this season and who show's up with just a 7 iron?
The end of the "quiver" ?
'Skis' works for me. I have skis that all have personalities, a feel to them, and even if they are both 100mm, they have a completely differeent ride. so I pick the ride I'm stoked on that day. I see it like a 6 car garage with a full spectrum of wonderful machines, a 7 series BMW to a Ferrari, and a Cobra, and a......
"In mathematics, a quiver is a directed graph where loops and multiple arrows between two vertices are allowed, i.e. a multidigraph. They are commonly used in representation theory: a representation, V, of a quiver assigns a vector space V(x) to each vertex x of the quiver and a linear map V(a) to each arrow a.
If K is a field and Γ is a quiver, then the quiver algebra or path algebra KΓ is defined as follows. A path in Γ is a sequence of arrows a1 a2 a3 ... an such that the head of ai+1 = tail of ai, using the convention of concatenating paths from right to left. Then the path algebra is a vector space having all the paths (of length ≥ 0) in the quiver as basis, and multiplication given by concatenation of paths. If two paths cannot be concatenated because the end vertex of the first is not equal to the starting vertex of the second, their product is defined to be zero. This defines an associative algebra over K. This algebra has a unit element if and only if the quiver has only finitely many vertices. In this case, the modules over KΓ are naturally identified with the representations of Γ.
If the quiver has finitely many vertices and arrows, and the end vertex and starting vertex of any path are always distinct (i.e. Q has no oriented cycles), then KΓ is a finite-dimensional hereditary algebra over K."
Which explains perfectly why we should continue to use "Quiver" when refering to a selection of skis!