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# How Much Force would be required?

I have acquired a pair of mint Explosivs in a 173. That is one size up from my standard length for skiing this model. I've had this ski (two pairs) over the last 5 or 6 years. It's no longer my daily ride, but I like em. So here's the queston. The 173's are for a skier about 165lb. That skier would be able to reverse the camber in turns from about 15 - 25 mph. How much faster would I, at 135lbs, have to go to apply the same amount of force. I started the calculations, but got impatient. Newtons, time is used not speed, and so forth. Engineers out there, how bout it? (had a pair of G-31's in a 178 and they were awesome: above a certain speed)
Off the top of my head.
F=ma=m (V^2)/(r)
Same turn with 135/165 of the mass would require a v of the square root of (165/135) times as fast, only about 10% faster, to obtain the required sideways force out of the turn.

Problem is you can't increase your down force, eventually you will reach a limit of not enough downwards pressure along the length of the ski edge to bite into ice.
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