Take this test:

Something was later suggested for those with no competition experience, so you don't divide by zero--if you have no points or results, take a skier who you've skied with who does have results or points in a discipline you might be involved in, and estimate your own ability as a percentage of theirs. Then take the points that the skier you're comparing yourself to would have received in that last step, multiply by the percent (as a decimal), and add the result to your own number. So if you've skied with someone who has 90 FIS points, and you think you're 70% the racer (or bump skier, or whatever) he is, then you take .75 of his points (since that's what you do with FIS points in this formula), put 100 over that number, and multiply the result by your number.

[ November 04, 2003, 09:52 PM: Message edited by: Pete Zehut ]

Quote:

Simply take: (number of years skiing+avg. of days skied per year for any five year period)*(1+max. number of rotations you can make)*percentage, in decimal form, you stick said rotations+your biggest drop in feet [subtract ten if you didn't ski cleanly away] Multiply the above by the number of inverts you can pull plus one, add the maximum length of rail you've ever slid in feet (happy, Jay?), then multiply by the sum of the steepest thing you've ever skied (avg. steepness in degrees) and the vertical drop of that thing (in feet). Then, either: Take the number and multiply by 100/your best USSA points (or .75 your best FIS points) in any discipline (except ballet), if you've ever had such points. or take the number and do one of the following with your best competition result: multiply by 20/your result for a national, pro-level competition (X Games, for example) multiply by 10/your result for a regional, pro-level competition (invitationals or opens that attract sponsored athletes) multiply by 3/your result a local mountain competition (weekly race series at your home mountain, for example) You can apply whatever combination of the above (but only choosing one where there are options) yields the highest score. |

[ November 04, 2003, 09:52 PM: Message edited by: Pete Zehut ]