Originally Posted by jhcooley
We will grant that it is difficult to control the pressure so precisely that it is always exactly constant.
Nonetheless, it is not necessary to actively reduce pressure to steer the skis. Indeed, it is quite possible to steer the skis even when there is temporarily more pressure than that provided by just your own weight. All that is necessary is to flatten the skis relative to the snow so that release is achieved. Nothing else. Of course, you can also take advantage of the shapes of the moguls to do at least some of your steering while all the pressure is concentrated under foot, with little pressure at the tips and tails. But it's not required. We will grant that it would be very difficult to add pivot if your feet are in the trench and the shape of the moguls is adding a lot of extra pressure to the tips and tails - so you use strategy, not unweighting, to avoid that situation.
You don't actively have to reduce pressure to steer the skis in the bumps because every other second you have a bump pushing you up. The only thing you need to do is to manage this pressure. Absorb the bumps. Flex with your knees. Extend again. In between turn. I don't think this will get us anywhere....
This is where you disagree with almost everyone else here. You believe that skis cannot be steered unless they are somehow unweighted.
This is not what Im saying. Im saying that unweighting at initiation will give you momentum to steer your skis into a brushed turn. Let me rephrase that: I believe that skis cannot be steered unless they are somehow weighted.
Consider the pivot slip. It is done on groomed snow, so that there is pressure on the full length of the ski, and I claim it is done without unweighting.
But your skis are not turning anywhere. You are slipping down the fall line.
Consider the wedge Christie. Like the pivot slip, it requires a release of the downhill ski and guidance of that ski down the hill. As an introductory move, it is done without requiring unweighting.
A wedge turn in general does not require unweighting. That is correct. That's why its a beginners turn. And skis are not parallel when turning. But its not the release of the outside ski that is producing the turn. Its the new outside wedging ski.
And yet, the moves required for a pivot slip or a wedge Christie are the same as those required to initiate a true parallel turn.
What you are saying is that the move required for a true parallel turn is the release of old edges and turning of the feet..... hmmm...... I wonder if it would work in powder or crud!
Flatten the ski to release. I don't care whether you extend or flex or neither one. Flatten. As soon as the ski releases, it becomes steerable.
When you initiate a true parallel turn by unweighting you flatten the skis to release them, yes. Your last sentence is not correct because as soon as the ski releases it starts to slip sideways. That's the reason you unweight. To prevent it from slipping sideways at initiation.
And if you don't flatten it, or can't or won't flatten it for some reason, then you have to unweight to achieve release.
No. The whole ide with unweighting is that you will keep on going the same direction as you did before the edge change. After you regain your pressure and you are on your new edges you steer the skis into the fall line and around in the other direction. A good way of finding out why you need to unweight is to go ski some powder.
We might also note that the stem turn, as distinct from the wedge Christie, does indeed require sequential unweighting because the old outside/new inside ski does not release until pressure is actively transferred to the new outside ski.
This is correct.
Flatten. Release. That is all.
Unweight and release. Weight and steer. That's all