Reading all these reviews, I notice a distinct difference in impressions on how a ski feels in terms of stiffness when it's a lighter vs heavier skier. And that got me thinking.......how to measure the force exerted on a ski relative to body weight? That would help explain why such differences in opinions of skis and how stiff they are, if it's a noodle, etc.
I understand F=mA, but how do we determine A? If Skier X is going at Y speed, that doesn't provide for Acceleration since that's defined as change over time. So then it's only in the turns apparently when "actual" force is exerted and when the stiffness is truly noticed (not on the flats obviously, since flex/stiffness is felt in response to force applied, primarily in the turns). So, how is that determined to solve the equation??
My curiosity is this: Say I weigh 80kg and am on Ski Z but someone else is 100kg on Ski Z, going at the same speed, with the same exact turns, what is the difference in force being against on the ski? The REASON for this is it should give some indication of the difference being felt in skis that are stiff for some but not others. I had a pair of skis that felt good when I was 30lbs heavier. But since I've lost the weight they feel like planks and I get seriously bounced around at speed. I would love to know the actual difference in force being applied on that ski since I'm 30lbs lighter now. And this would also then give some indication why a ski gets excellent reviews for a 170lb guy but called a noodle for a 205lb guy (for example). I truly feel this is the missing link in ski reviews, as a heavier person simply cannot relate to a review written by a lightweight, especially considering the forces being applied are magnified at higher speeds. So that 30lbs difference would seem even MORE significant at, say 50km/h carving down a run. See my point?
Maybe this is all foolishness, but I would appreciate any input/help. I'm not a mathematician; I'm a concept guy. I have the crazy thought, but not the knowledge how to solve the question LOL.