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Originally Posted by HeluvaSkier
...Someone should also employ Physicsman to calculate the exact distance traveled by each skier, and then have him calculate thier average speed over the distance... Just to prove how much more ground is covered and the higher speeds attained by carving. He likes that kind of stuff, so i bet if someone paid for him to attend the event, he would work it for free...
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Hey, Greg - How ya doing? I haven't heard from you for a while - check your private messages.
Now, about me showing up a Fastman-TCS race, based on past dealings I've had with TCS, I suspect I'm not exactly his favorite skiing buddy.

However, if someone wants to send me a ticket, and the race occurs after the semester is over next fall, I would be happy to stand at the finish line and applaud appropriately as Rick and every one of his racing students leaves TCS in the dust.
BTW, here's the formula I think you are looking for:

What is says is that the ratio of the actual distance covered by a racer going around gates to the distance covered by someone straightlining the course down the center of the offset gates is approximately equal to the square root of (one plus (two times the average gate offset divided by the average downhill spacing between two successive RH or LH gates)squared).
Thus, if the average offset of gates on a course is 100 feet, and successive RH (or LH) gates are 200 feet apart (in the direction of the fall line), then a racer will cover 1.41 times the distance covered by someone straightlining the course. In terms of speed, if these two skiers arrive simultaneously at the finish line, the one going around the gates will have had to go 1.41 times faster for this to happen. So, if the straightliner is going 50 km/hr, the person going around the gates will have to be going at least 70.7 km/hr on average in order to tie the straightliner.
All the best,
Tom / PM